What Is the Molarity of 468 mg MgI2 in a 50 ml Solution?

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SUMMARY

The molarity of 468 mg of magnesium iodide (MgI2) in a 50 ml solution is calculated to be 0.0337 M. This is derived from converting 0.468 g of MgI2 into moles, resulting in 0.001683 moles. Dividing the number of moles by the volume in liters (0.05 L) confirms the molarity as 0.0337 M. The discussion highlights the importance of accurate calculations in determining molarity.

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468 mg MgI2 in 50 ml solution, determine molarity.

.0297
.0337
.0930
.0107
.0651

i did not check my work but i got .337, not .0337.

i asked the professor about it and she assured me the correct answer was there, so i just marked .0337.
 
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Well damn, ill have to look at my work then
 

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