What Is the Molarity of 70% TBHP Solution?

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Discussion Overview

The discussion revolves around calculating the molarity of a 70% TBHP (tert-Butyl hydroperoxide) solution, focusing on the implications of the given density and weight/weight percentage (w/w%). Participants explore the relationship between density, weight percentage, and molarity in the context of a chemistry homework problem.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents an initial calculation for molarity using density and formula weight, arriving at 10.4M but expresses uncertainty about the relevance of the 70% and w/w%.
  • Another participant suggests that "Molarity of 70%" implies a multiplication of a one molarity solution by 0.7, questioning the understanding of what a one molarity solution would be.
  • A subsequent reply recalculates the molarity to 7.28mol/L, incorporating the 70% factor into the density-based calculation, but seeks confirmation of correctness.
  • One participant asserts that the problem is asking for molarity and that the provided density indicates a w/w% context.
  • Another participant clarifies that "Molarity of 70%" should be interpreted as the molarity of a 70% solution of TBHP, emphasizing that 70% is likely referring to w/w%.

Areas of Agreement / Disagreement

Participants express differing interpretations of the term "Molarity of 70%" and its implications for the calculation. There is no consensus on the correct approach or final answer, as multiple interpretations and calculations are presented.

Contextual Notes

Participants have not fully resolved the assumptions regarding the interpretation of weight percentage and its application to the molarity calculation. The relationship between density, weight percentage, and molarity remains a point of contention.

amorale
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Homework Statement


What is the Molarity of 70% TBHP?


Homework Equations


Given: d=.937g/ml, FW=90.12g , w/w%?


The Attempt at a Solution


1000mL x (0.937g/mL) x (1mol/90.12g) = 10.4M

That is what I got but idk what to do with the 70% or that w/w%
or is that right the way I did it?
 
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"Molarity of 70%" means .7 times one molarity. Do you know what a one molarity solution would be?
 
So this is what I came up with now:

1000mL x (0.937g/mL) x (.7) x (1mol/90.12g) = 7.28mol/L

Is this correct now?
 
If they are asking the molarity and they have given you density, then it is definitely w/w%
 
HallsofIvy said:
"Molarity of 70%" means .7 times one molarity.

No, in this context it means molarity of 70% solution of TBHP, 70% being most likely w/w.
 

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