- #1

fishingspree2

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## Homework Statement

Find the required mass of Al

_{2}(SO

_{4})

_{3}.18H

_{2}O (molar mass = 666 g/mol) to prepare 50 mL of an aqueous solution, concentration = 40 mg of Al

^{3+}per mL

## The Attempt at a Solution

0.04 grams of Al

^{3+}/1mL = x g / 50 mL

x = 2g

I think this is the required mass of Al

^{3+}, now I don't know how to find how much Al

_{2}(SO

_{4})

_{3}.18H

_{2}O do I need to get 2 g of Al

^{3+}

The answer is 24.7g