What Is the Molecular Formula of the Hydrocarbon?

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SUMMARY

The discussion focuses on calculating the molecular formula of a hydrocarbon based on its combustion reaction. The hydrocarbon, represented as CxHy, reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). The correct stoichiometric equation is CxHy + (x+y/4)O2 → xCO2 + y/2H2O, which balances the elements involved. Participants emphasized the importance of balancing the equation correctly to derive the values of x and y for the hydrocarbon's molecular formula.

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Homework Statement



0.1 dm^3 of a gaseous hydrocarbon may require 0.45 dm^3 of oxygen for a complete combustion to give 300 cm^3 of Carbon dioxide. All volumes are measured in the same environment. Calculate the molecular formula of the hydrocarbon.

The Attempt at a Solution



i tried getting the gdc of 10, 30 and 45 =90. and the have like

9 CxHy + 2 O2 --> 3 CO2 + H2O

but I cannot go further than this. please help. Thanks.
 
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as for the formula you have taken.. i don't understand why you've taken the GCD, but it is fundamentally wrong as the oxygen is not balanced on both sides [and neither is carbon or hydrogen].

What you need is a equation which is prefixed and suffixed by variables on both the sides to get you a linear equation which you can then solve...
 
Can you think of a way to calculate the amount of carbon in CO2 and hydrogen in H2O? You have a good start here:
CxHy + O2 --> CO2 + H2O
I've removed the prefixes you had (the '9', '2' and '3'). Can you solve it in terms of 'x' and 'y'?
 
CxHy + (x+y/4)O2 --> xCO2 +y/2H2O

thats the correct answer from ccea spec for alevel chemistry =]
 

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