What is the moment of inertia of the particle at the end of the meter stick?

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SUMMARY

The moment of inertia of a particle is calculated using the formula I = mr², where m is the mass of the particle and r is the distance from the axis of rotation. In this discussion, a particle with a mass of 0.400 kg is attached to the 100-cm mark of a meter stick, which has a mass of 0.100 kg. The system's angular momentum is analyzed for two pivot points: the 50.0-cm mark and the 0-cm mark, with an angular speed of 4.00 rad/s. The moment of inertia for the particle at the end of the meter stick is determined based on its distance from the pivot point.

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Moment of Inertia

A particle of mass 0.400 kg is attached to the 100-cm mark of a meter stick of mass 0.100 kg. The meter stick rotates on a horizontal, frictionless table with an angular speed of 4.00 rad/s. Calculate the angular momentum of the system when the stick is pivoted about an axis (a) perpendicular to the table through the 50.0-cm mark and (b) perpendicular to the table through the 0-cm mark.

What is the moment of intertia of the particle at the end of the meter stick? I know how to find the moment of intertia of the meter stick.
 
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The moment of inertia of a particle is mr^2
 
thank you
 

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