- #1
chikis
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Homework Statement
Please I need help with this question:
A man drives to a car park at an average speed of 40 km/hr and then walks to his office at average speed of 6km/h. The total journey takes him 25 minutes. One day his car breaks down and he has to walk three times as far, so arriving at his office 17 minutes late. How far is it to his office?
Homework Equations
time = distance /speed
The Attempt at a Solution
x = distance driven (normally)
> y = distance walked (normally)
>
For the normal situation,
5/12 = x/40 + y/6
When the car breaks down, he walked three times as far.That means he walked three times the distance he used to cover when his car had a mechanical fault. This distance include (3x) 3 times the distance to the car park and (3y) 3 times the distance to the office. Am saying this because on that the day he had no car at his disposal, so he made the journey with his leg i.e is the journey to the car park and to the office. So because of this reason the second equation becomes
3x/40 + 3y/6 = 7/10h
Am I equations correct?