What is the new separation between the charges?

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kdrobey
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Homework Statement




Two positive point charges are held in place, 0.86 m apart. They are then moved so that their electric potential energy doubles. What is the new separation between the charges?

Homework Equations



kq/r

The Attempt at a Solution


had PEb=KQaQb/d=2EPEa, then did KQaQb/d=2(KQaQb/.86. but cannot figure out how to solve it further
 
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kdrobey said:
... then did KQaQb/d=2(KQaQb/.86.
This is good. Simply and solve for d. Start by canceling everything that can be canceled from both sides of the equation.
 
both sides of the equation had KQaQb, i canceled the part out on both sides, leaving, 1/d=2(1/.86). then 1=2.32d. d=.43?