What is the new separation between the charges?

  • Thread starter kdrobey
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  • #1
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Homework Statement




Two positive point charges are held in place, 0.86 m apart. They are then moved so that their electric potential energy doubles. What is the new separation between the charges?

Homework Equations



kq/r

The Attempt at a Solution


had PEb=KQaQb/d=2EPEa, then did KQaQb/d=2(KQaQb/.86. but cannot figure out how to solve it further
 

Answers and Replies

  • #2
Doc Al
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... then did KQaQb/d=2(KQaQb/.86.
This is good. Simply and solve for d. Start by canceling everything that can be canceled from both sides of the equation.
 
  • #3
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both sides of the equation had KQaQb, i cancelled the part out on both sides, leaving, 1/d=2(1/.86). then 1=2.32d. d=.43?
 
  • #4
Doc Al
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Looks good to me.
 
  • #5
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awesome, thanks
 

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