What is the next step for determining convergence or divergence of this series?

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Homework Help Overview

The discussion revolves around determining the convergence or divergence of the series \(\sum^{∞}_{n=1} (-1)^n \frac{6n^8 + 3}{3n^5 + 3}\). Participants are exploring concepts related to series convergence, particularly focusing on absolute and conditional convergence.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the applicability of the alternating series test, noting that the function appears to be increasing rather than decreasing. There is also a suggestion to consider the divergence test and to analyze the behavior of the series terms.

Discussion Status

The discussion includes various interpretations of the series behavior, with some participants suggesting that the terms do not approach zero, which may indicate divergence. However, there is no explicit consensus on the final conclusion regarding convergence or divergence.

Contextual Notes

Participants mention constraints related to the alternating series test and the behavior of the sequence involved, indicating a focus on the properties of the series terms.

whatlifeforme
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Homework Statement


determine either absolute convergence, conditional convergence, or divergence for the series.

Homework Equations


\displaystyle \sum^{∞}_{n=1} (-1)^n \frac{6n^8 + 3}{3n^5 + 3}

The Attempt at a Solution


I cannot use the alternating series test since the function is increasing not decreasing.What should i do next?
 
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whatlifeforme said:

Homework Statement


determine either absolute convergence, conditional convergence, or divergence for the series.


Homework Equations


\displaystyle \sum^{∞}_{n=1} (-1)^n \frac{6n^8 + 3}{3n^5 + 3}


The Attempt at a Solution


I cannot use the alternating series test since the function is increasing not decreasing.What should i do next?
Since the sequence (apart from the (-1)n factor) is increasing, doesn't that give you a hint as to what the series is doing? It might help to write a few terms in the series.
 
can i use the divergence test?
 
Yep, it diverges since its terms do not approach zero.
 
HS-Scientist said:
Yep, it diverges since its terms do not approach zero.

thanks.
 

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