What is the Nuclear Spin of Fluorine-19 and How is it Calculated?

[Clear Mind]

I was trying to calculate the $^{19}_{9}F_{10}$ nuclear spin using the nuclear shell method. From what i know the nuclear spin for a nucleous with odd $A$ is the total angular momentum $J$ of the stand-alone nucleon:
P: $(1d_{5 \backslash 2})^1$ (stand-alone nucleon)
N: $(1d_{5 \backslash 2})^2$
which in this case is a proton with $J=\frac{5}{2}$ so it leads to a nuclear spin of $I=\frac{5}{2}$. But this isn't what i found in lecture, from the pdg (http://ie.lbl.gov/toi/nuclide.asp?iZA=90019) $^{19}_{9}F_{10}$ result to have $I=\frac{1}{2}$.
I missed something?

 

[ChrisVer]

Your filling is incorrect.
You have 9 protons and 10 neutrons. Well no need to care about the neutrons, since they will pile up into pairs together (even number). From the protons you will have 1 extra remaining unpaired. You will fill until 1d_{5/2} . So your nucleus spin will be determined by the unpaired proton, the proton has spin 1/2 so 1/2 is the spin of your nucleus...<br /> Sometimes things are mixed with J, S in nuclear physics, calling both of them "spins". The total angular momentum is indeed 5/2, the spin is 1/2.

 

[Clear Mind]

Your filling is incorrect.
You have 9 protons and 10 neutrons. Well no need to care about the neutrons, since they will pile up into pairs together (even number). From the protons you will have 1 extra remaining unpaired. You will fill until 1d_{5/2} . So your nucleus spin will be determined by the unpaired proton, the proton has spin 1/2 so 1/2 is the spin of your nucleus...<br /> Sometimes things are mixed with J, S in nuclear physics, calling both of them "spins". The total angular momentum is indeed 5/2, the spin is 1/2.

<br /> <br /> My apologies but I'm not understanfding what you mean, for example take the $^{43}_{21}Sc_{22}$. It have 22 neutron (so we don't need to care about), and 21 proton which are filled until $1f_{7 \backslash 2}$. There's only one proton unpaired so nuclear spin $I$ should be $\frac{1}{2}$ (equal to the spin of the proton) but is $I=\frac{7}{2}$ (always from pdg <a href="http://ie.lbl.gov/toi/nuclide.asp?iZA=210043" target="_blank" class="link link--external" rel="nofollow ugc noopener">http://ie.lbl.gov/toi/nuclide.asp?iZA=210043</a>)

 

[Vanadium 50]

I don't understand what either of you is saying. 19F can be modeled as an 18O plus a proton. 18O is 0+, so 19F is 1/2+.

 

[statefxn]

have you failed to recognize the difference between net spin and total magnetic moment?