What Is the Optimal Location for a Junction Box to Minimize Wiring Distance?

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SUMMARY

The optimal location for the junction box to minimize wiring distance between two isolated farms, located 12km apart, is derived from a mathematical analysis involving the distance formula. The initial approach incorrectly focused on minimizing the distance to one house only, resulting in a junction box placement at (0,0) which is 20km from the main road. The correct method involves minimizing the total wire length, represented by the equation (20-x) + 2*[x^2 + 36]^0.5, leading to a more accurate placement of the junction box.

PREREQUISITES
  • Understanding of the distance formula: D = [(x2-x1)^2 + (y2-y1)^2]^0.5
  • Basic calculus concepts, specifically derivatives for optimization
  • Familiarity with Pythagorean theorem applications
  • Knowledge of coordinate geometry for placing points on a plane
NEXT STEPS
  • Learn how to apply calculus for optimization problems in real-world scenarios
  • Study the implications of minimizing multiple variables in distance calculations
  • Explore coordinate geometry techniques for solving similar geometric problems
  • Investigate practical applications of junction box placement in electrical engineering
USEFUL FOR

Mathematicians, electrical engineers, and anyone involved in optimizing infrastructure layout, particularly in rural settings.

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Homework Statement



Two isolated farms are 12km apart on a straight country road that runs parallel to the main highway 20km away. The power company decides to run a wire from the highway to the junction box, and from there, wired of equal length to two houses. Where should the junction box be placed to minimize the length of wire needed

Homework Equations



[(x2-x1)^2+(y2-y1)^2]^0.5=D

The Attempt at a Solution



I split the distance between the farms in half and used the midpoint as (0,0)

I set the juntion box as (x,0) and one farm house as (0,6)

putting those into the distance formula I got D=[x^2+36]^0.5

taking the derivative of D^2 i get 2x, setting it to 0=2x gives me x=0. a numberline test shows 0 is a min value

after that I put the 0 back in my origiinal D equation which gave me a distance of 6km, however this answer feels wrong since the box would be 20km from the main road. feedback is appreciated
 
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I think they want you to minimize the length of ALL of the wire used. Not just the wire connecting the one house to the junction box. Try minimizing (20-x)+2*[x^2+36]^0.5.
 
annddd that would make more sense, thanks. I was hoping to get a distance and solve using pythagorean, but looking at what you did that would be the wrong direction.
 
Last edited:

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