• Support PF! Buy your school textbooks, materials and every day products Here!

What is the original kinetic energy of the player?

  • Thread starter needhelp83
  • Start date
  • #1
199
0
A 95-kg football player traveling 5.0 m/s is stopped in 1.0 s by a tackler.
a. What is the original kinetic energy of the player?
b. What average power is required to stop him?

a.
K=(1/2)mv2
K=(1/2)(9500 g)(5.0 m/s)2= 118,750 J
b.
P=w/t
P=118750 J/1.0 s= 118750 W


Would this be correct because of the work-energy principle?
 

Answers and Replies

  • #2
radou
Homework Helper
3,115
6
Looks okay, but I don't see why you should convert [kg] to [g].
 

Related Threads on What is the original kinetic energy of the player?

Replies
3
Views
6K
Replies
30
Views
616
Replies
12
Views
10K
Replies
3
Views
1K
Replies
6
Views
35K
Replies
3
Views
2K
Replies
22
Views
3K
Replies
1
Views
11K
Replies
1
Views
2K
Top