What is the original kinetic energy of the player?

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SUMMARY

The original kinetic energy of a 95-kg football player traveling at 5.0 m/s is calculated using the formula K=(1/2)mv², resulting in 118,750 Joules. To determine the average power required to stop the player in 1.0 second, the power formula P=w/t is applied, yielding 118,750 Watts. The discussion confirms the calculations align with the work-energy principle, although converting kilograms to grams is unnecessary for this context.

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A 95-kg football player traveling 5.0 m/s is stopped in 1.0 s by a tackler.
a. What is the original kinetic energy of the player?
b. What average power is required to stop him?

a.
K=(1/2)mv2
K=(1/2)(9500 g)(5.0 m/s)2= 118,750 J
b.
P=w/t
P=118750 J/1.0 s= 118750 W


Would this be correct because of the work-energy principle?
 
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Looks okay, but I don't see why you should convert [kg] to [g].
 

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