What Is the Oscillation Period of a Rod Attached to a Spring?

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SUMMARY

The oscillation period of a 200g uniform rod, pivoted at one end and attached to a spring with a constant of 3 N/m, can be calculated using principles of simple harmonic motion. The rod's length is 20 cm, and its angular frequency without the spring is derived from the formula sqrt[(m*g*L)/I], where I is the moment of inertia. To find the total period, the contributions from both the rod and the spring must be considered, specifically using the formula for the period of a simple harmonic oscillator, T = 2π√(m/k).

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Familiarity with angular frequency and moment of inertia calculations
  • Knowledge of Hooke's Law and spring constants
  • Basic physics of pendulums and oscillatory systems
NEXT STEPS
  • Calculate the moment of inertia for the rod using I = (1/3)mL²
  • Learn how to derive the total period of combined oscillatory systems
  • Explore the effects of damping on oscillation periods
  • Investigate the relationship between angular frequency and linear frequency in oscillatory motion
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Physics students, educators, and anyone studying dynamics of oscillatory systems, particularly those involving combined mechanical components like rods and springs.

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Homework Statement


A 200g uniform rod is pivoted at one end. The other end is attached to a horizontal spring. The spring is neither stretched nor compressed when the rod hangs straight down. What is the rod's oscillation period? You can assume that the rod's angle from the vertical is always small. The rod's length is 20 cm and the spring's constant is 3N/m.



Homework Equations





The Attempt at a Solution



Without the spring the rod's angular frequency would be sqrt[(.200)(9.80)(.10m)/(.0027kgm^2) Then I could go to period. Will someone tell me how I can get the period for the spring? The problem is I am used to doing problems with just a spring and a block, but I am not quite sure how to deal with the extended object. Would I just use omega= sqrt [k/m] with mass .200kg and k = 3.0 N/m? Then I could go to period, and maybe add the two period together?
 
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For a simple harmonic oscillator the restoring force is F = ma = -kx. what is the total restoring force for the pendulum string combination? If that is in the form -kx you can use the equaton for the period of a simple harmonic oscillator.
 

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