What Is the Oxygen Concentration at the Interior End of a Trachea?

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SUMMARY

The discussion focuses on calculating the oxygen concentration at the interior end of a trachea, given its length of 1.17 mm, a cross-sectional area of 1.01 x 10-9 m2, an external oxygen concentration of 0.659 kg/m3, a diffusion constant of 1.99 x 10-5 m2/s, and a diffusion mass rate of 1.50 x 10-12 kg/s. The correct formula to determine the change in concentration (deltaC) is deltaC = mL / DA. The final calculated oxygen concentration at the interior end of the trachea is 0.0873 kg/m3, correcting the initial miscalculation of 8.73E8 kg/s.

PREREQUISITES
  • Understanding of diffusion principles in gases
  • Familiarity with the equation m = (DA(deltaC))t / L
  • Knowledge of units for mass concentration (kg/m3)
  • Basic algebra for rearranging equations
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  • Study the implications of diffusion constants in biological systems
  • Learn about the effects of tracheal dimensions on gas exchange efficiency
  • Explore advanced diffusion equations and their applications in physiology
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Biologists, physiologists, and researchers studying respiratory systems in insects, as well as students learning about gas diffusion principles in biological contexts.

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Suppose that a tracheae is 1.17 mm long with a cross-sectional area of 1.01 x 10-9m2. The concentration of oxygen in the air outside the insect is 0.659 kg/m3, and the diffusion constant is 1.99 x 10-5 m2/s. If the mass per second of oxygen is diffusing through a trachea is 1.50 x 10-12 kg/s, then find the oxygen concentration at the interior end of the tube.

m= (DA(deltaC))t / L



I re-arranged the equation to solve for the change in concentration, (delta)C.
deltaC = mL / DA. I know the given value for the outside concentration will be moved over to the other side. I think that the concentration given for the outside of the insect would be the same as initial concentration and the concentration I am solving for would be the final concentration but not exactly sure on this. So I added the concentration given to the other side of the equation to isolate the final concentration. I calculated this to be 8.73E8 kg/s, however this is incorrect. Any suggestions?
 
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haleyy89 said:
Suppose that a tracheae is 1.17 mm long with a cross-sectional area of 1.01 x 10-9m2. The concentration of oxygen in the air outside the insect is 0.659 kg/m3, and the diffusion constant is 1.99 x 10-5 m2/s. If the mass per second of oxygen is diffusing through a trachea is 1.50 x 10-12 kg/s, then find the oxygen concentration at the interior end of the tube.

m= (DA(deltaC))t / L

I re-arranged the equation to solve for the change in concentration, (delta)C.
deltaC = mL / DA.
You lost the 't' when re-arranging.

to isolate the final concentration. I calculated this to be 8.73E8 kg/s, however this is incorrect. Any suggestions?
Using your formula and data, I make delta C to be 0.0873 kg/m3
 

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