What is the parachutist's position after 10 seconds?

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SUMMARY

The discussion focuses on calculating the position of a parachutist after 10 seconds, given the initial position S = [0, 5000, 0], initial velocity v = [300, 0, 100], and constant acceleration a = [2, -9.81, 0]. The participant seeks clarification on using the equations of motion in three dimensions, specifically the formulas for constant acceleration: x(t) = xo + voxt + (1/2)axt², y(t) = yo + voy*t + (1/2)ayt², and z(t) = zo + vozt + (1/2)azt². The discussion confirms that these equations can be applied to determine the parachutist's position in a three-dimensional space.

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controlfreaks
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Homework Statement


A parachutist jumps from a plane which is at position S = [0, 5000, 0] at time t = 0. The starting velocity of parachutist is v = [300, 0, 100] and we're assuming the parachutists falls like a particle with constant acceleration a = [2, -9.81, 0].

I need to find the parachutists position after 10 seconds.


Homework Equations


the only equations i have here are the 3 for acceleration under constant motion but these assume a one directional system.


The Attempt at a Solution


i can't attempt a solution without knowing where I'm starting here with the 3 dimensions so if anyone could give me a hand with what equations i need to use then i should be good to go!
 
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If you know what happens in 1-D, you can easily generalize to 3-D. All you need to do is change symbols. The most general expressions for constant acceleration are

x(t) = xo+voxt + (1/2)axt2
y(t) = yo+voyt + (1/2)ayt2
z(t) = zo+vozt + (1/2)azt2

In 3-D the position of the parachutist at any time t is [x(t), y(t), z(t)].
 
thank you so much, that's perfect.

just didn't know if we we're dealing with angular velocity or something more complicated here.

cheers!
 

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