What is the parallel-component of the weight

[Jess048]

A 50 kg trunk rest on a ramp at 18 degrees. What is the parallel-component of the weight?
a. 15.5 N
b. 47.6 N
c. 151 N
d. 466 N

So far I got:
I used the formula Fgx = W sin 0.

Fgx= -(490 N) sin(18)
My answer was 368, as you see it is not one of the choices. Am i leaving out a step or am I not finished with the problem. Can someone clarify please thanx.

 

[Dick]

You are computing the sine of 18 radians, not 18 degrees.

 

[Jess048]

Oh ok so the answer would be C