- #1

Engr.abshir

- 5

- 0

## Homework Statement

A 64 microC charge is locate 30 cm to the left of a 16 micro C charge. What is the resultant force

on a -12 micro C charge positioned exactly 50 mm below the 16 micro C charge?

## Homework Equations

coulomb law f=k*qq/(r^2),resultant force,resolve into x and y component.

## The Attempt at a Solution

the first three steps are straightforward

first step

using Pythagoras rule gives s=58.3 mm and theta = 59.0 degree

the force b/w q1 and q2 using coulomb law i calculated

F13 = 2033 N.

similarly ,the force between q2 and q3, gives correctly

F 23= 691 N.

i am having trouble understanding these steps about resolving it into components.i need some revision here.

Fx = 0- F13 cos 59.0 (where does the zero come from?)

= -(2033 N) cos 59.0

which gives Fx = -1047 N

also

Fy = F23 + F13 sin 59.00(why add force 23)

= 691 N + (2033 N) sin 590

Fy = 2434 N

i can do the rest.

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