Calculating Weight Component on Hillside | Trig/Physics Homework Question

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Homework Help Overview

The problem involves calculating the component of a boulder's weight acting parallel to a hillside inclined at an angle (alpha) to the horizontal. The original poster is attempting to express this component in terms of the weight (w) and the angle (alpha).

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • The original poster attempts to find the parallel component of the weight using a trigonometric relationship but expresses uncertainty in their approach. Some participants suggest re-evaluating the geometry involved in the problem. Questions arise regarding the identification of the angle alpha and its relevance to the problem, as well as the foundational knowledge required for understanding the concepts involved.

Discussion Status

The discussion is ongoing, with participants exploring the geometric relationships and clarifying assumptions. Some guidance has been offered regarding the geometry of the situation, and there is a recognition of the need for a solid mathematical background to tackle the problem effectively.

Contextual Notes

The original poster notes that the problem is from a chapter that does not cover forces, which may contribute to their confusion. There is also a mention of the difficulty level of the problem in relation to the expected knowledge base.

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Homework Statement



A boulder of weight w rests on a hillside that rises at a constant angle (alpha) above the horizontal, as shown in the figure. The boulder's weight is a force on the boulder that has a direction vertically downward.

In terms of alpha and w, what is the component of the weight of the boulder in the direction parallel to the surface of the hill?

Homework Equations





The Attempt at a Solution



I put w/sin(alpha) but this is wrong. As you can see I made the component parallel to the slope of the hill x so that means that sin(alpha)=w/x...solve for x and I get x=w/sin(alpha).

Apparently this is totally wrong.

I attached the diagram to the problem. Thanks for the help
 

Attachments

Last edited:
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You might want to re-evaluate the geometry of the situation. See the attached diagram.
 

Attachments

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Ah okay thanks I would have never thought of that. How do we know that new angle is alpha? Is that common knowledge or a basic geometry fact? This problem was weird and hard for me because it is from chapter 1 of my book which covers models, measurements, and vectors. I read the whole chapter and it didn't discuss the concept of force at all. Thanks again.
 
maff is tuff said:
Ah okay thanks I would have never thought of that. How do we know that new angle is alpha? Is that common knowledge or a basic geometry fact? This problem was weird and hard for me because it is from chapter 1 of my book which covers models, measurements, and vectors. I read the whole chapter and it didn't discuss the concept of force at all. Thanks again.

The fact that the "new" angle shown in gneill's diagram is alpha is so fundamentally obvious from the basics of geometry that the fact that you even have to ask leads me to think that you do not have the basic math background that is expected before you get to trig. What grade are you in? What math have you already taken?
 
phinds said:
The fact that the "new" angle shown in gneill's diagram is alpha is so fundamentally obvious from the basics of geometry

It's obvious to me that it's the same angle just by inspection, but how would you prove it?

edit: Don't worry, just did it.
 
Last edited:
It looks obvious now that it is the same angle. If you tilt everything 90 degrees then the perpendicular-to-the-slant line becomes parallel to the slant and the straight down line becomes parallel to the ground. Sorry for the dumb question; I'll try to think things over more before I post.
 

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