What is the partial pressure of the NH3

Click For Summary
SUMMARY

The discussion focuses on calculating the partial pressure of ammonia (NH3) in a gas mixture consisting of methane (CH4), ammonia (NH3), and carbon dioxide (CO2) with a total pressure of 9.42 atm. Using Dalton's Law of Partial Pressure, the partial pressure of NH3 is determined by its mole fraction multiplied by the total pressure. The correct formula involves converting grams to moles for each gas and applying the equation: P(NH3) = (n(NH3)/n(total)) * 9.42 atm. The solution confirms that this method is accurate for finding the desired partial pressure.

PREREQUISITES
  • Understanding of Dalton's Law of Partial Pressure
  • Knowledge of the Ideal Gas Law
  • Ability to convert grams to moles using molar mass
  • Familiarity with mole fraction calculations
NEXT STEPS
  • Learn about Dalton's Law of Partial Pressure in detail
  • Study the Ideal Gas Law and its applications
  • Practice converting grams to moles for various compounds
  • Explore mole fraction calculations in gas mixtures
USEFUL FOR

Chemistry students, educators, and professionals involved in gas law applications and calculations, particularly those focusing on partial pressures in mixtures.

DallasMavs
Messages
3
Reaction score
0

Homework Statement


The combined pressure of 32.0 g of CH4, 64.2 g NH3, and 100 g of CO2 is 9.42 atm. What is the partial pressure of the NH3



Homework Equations


Dalton's Law of Partial Pressure = P=Pa +Pb + Pc ...
The individual partial pressure follow the ideal gas law. For component A, (Pa)V=(nA)RT where nA is the number of oles in component A

The Attempt at a Solution


I have converted all the grams to moles by dividing the grams by the compounds molar mass. I have no idea what to do from there. Someone please help.
 
Physics news on Phys.org
Partial pressure of any gas is its molefraction * total pressure.
so, for your problem it is

\frac{n_{NH_3}}{n_{total}}.(9.42)
 
So, I would take the moles of NH3 and divide that by the total number of moles (moles of NH3, CH4, and CO2). Than multiply that by the total pressure. Is that correct?
 
DallasMavs said:
So, I would take the moles of NH3 and divide that by the total number of moles (moles of NH3, CH4, and CO2). Than multiply that by the total pressure. Is that correct?
yes that's it
 
Thanks for the assistance
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
3
Views
2K
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
8K
Replies
3
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
1
Views
5K