Calculating the partial pressure of pure Zinc over a solution? over

Click For Summary
SUMMARY

The discussion focuses on calculating the partial pressure of pure zinc (PZn) over a solution containing 60 mol% copper and 40 mol% zinc at a temperature of 1200 K. The activity coefficient of zinc in liquid brass is defined by the equation RT ln γZn = -38,300 x2Cu, where xCu represents the mole fraction of copper. The vapor pressure of pure zinc at this temperature is given as 1.17 atm. The user seeks clarification on how to derive PZn using the Gibbs-Duhem relationship and questions the unit of the activity coefficient.

PREREQUISITES
  • Understanding of Gibbs-Duhem relationship
  • Knowledge of vapor pressure concepts
  • Familiarity with mole fractions in solutions
  • Basic thermodynamics principles
NEXT STEPS
  • Study the derivation of the Gibbs-Duhem relationship in detail
  • Learn about calculating partial pressures in multi-component systems
  • Explore the concept of activity coefficients and their significance in solutions
  • Review thermodynamic equations related to vapor-liquid equilibrium
USEFUL FOR

Chemical engineers, physical chemists, and students studying thermodynamics or solution chemistry will benefit from this discussion.

billboard
Messages
2
Reaction score
0

Homework Statement



The activity coefficient of zinc in liquid brass is given (in joules) by the following equation for
temperatures 1000-1500 K:
RT ln γZn = -38,300 x2Cu

where xCu is the mole fraction of copper. Calculate the partial pressure of pure zinc PZn over a
solution of 60 mol% copper and 40 mol % zinc at 1200 K. The vapor pressure of pure zinc is
1.17 atm at 1200 K.

Homework Equations



For dilute solutions: xs: mole fraction of solvent, xu: mole fraction of solute,
The vapour pressure of the solvent= Ps= P(pure)xs=P(pure)(1-xu) where is P(pure)=vapour pressure of the pure solvent.


Gibbs-Duhem Relationship=
lnaB
lnaA= - ∫ xB/ xa * d(lnaB)
-∞

The Attempt at a Solution



d (lnγA)= - XB/XA * d(lnγB) applying Gibbs-Duhem rel. in the form of this eqnn:
dxcu= -dXzn
lnγCu= - 38.300/ RT * X^2Zn

How can i get the partial pressure of pure zinc PZn?

Thanks! :)
 
Physics news on Phys.org
Activity coefficient in Joules? Shouldn't it be unitless?
 

Similar threads

Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
2
Views
3K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
17K
  • · Replies 2 ·
Replies
2
Views
2K