What is the percentage by mass of ammonium phosphate in the fertilizer?

  • Thread starter Thread starter littlebearrrr
  • Start date Start date
  • Tags Tags
    Mass
Click For Summary
The discussion focuses on calculating the percentage by mass of ammonium phosphate in a fertilizer sample. A 7.225 g fertilizer sample reacts with barium chloride, producing 3.741 g of barium phosphate. To find the percentage, the moles of barium phosphate are converted to moles of ammonium phosphate, which are then used to determine the grams of ammonium phosphate. The final calculation shows that ammonium phosphate constitutes 25.65% of the fertilizer's mass. The clarification that the fertilizer is a mixture and not solely ammonium phosphate is emphasized.
littlebearrrr
Messages
25
Reaction score
0

Homework Statement


Many fertilizers contain ammonium phosphate as a source of phosphorus and nitrogen. A 7.225 g sample of a fertilizer is dissolved in water and mixed with excess barium chloride solution, and the following reaction occurs:

2(NH4)3PO4(aq) + 3BaCl2(aq) -> Ba3(PO4)2(s) + 6NH4Cl(aq)

The product mixture is found to contain 3.741 g of barium phosphate. Using this info, calculate the percentage by mass of ammonium phosphate in the fertilizer.

Homework Equations



% by mass = grams of fertilizer/molar mass of fertilizer x 100
(unsure if that's correct, but that's what I think it should be)

The Attempt at a Solution



I started by taking the given amount of barium phosphate to find moles of ammonium phosphate. I think I need to use that to find grams of ammonium phosphate. However, I am also having difficulty trying to understand what the problem is specifying as the fertilizer. Is it the ammonium phosphate AND the barium chloride, or just the ammonium phosphate?
 
Physics news on Phys.org
littlebearrrr said:

Homework Equations



% by mass = grams of fertilizer/molar mass of fertilizer x 100
(unsure if that's correct, but that's what I think it should be)
There is no such thing as the molar mass of a fertilizer, as it is a mixture. You want to know what percentage of the total mass is due to ammonium phosphate:

% by mass = mass of ammonium phosphate / total mass of fertilizer

littlebearrrr said:

The Attempt at a Solution



I started by taking the given amount of barium phosphate to find moles of ammonium phosphate.
You can do that. You can also calculate everything using just masses.

littlebearrrr said:
I think I need to use that to find grams of ammonium phosphate. However, I am also having difficulty trying to understand what the problem is specifying as the fertilizer. Is it the ammonium phosphate AND the barium chloride, or just the ammonium phosphate?
The fertilizer is a mixture of ammonium phosphate and other stuff. The barium chloride is added in the lab.
 
Thank you DrClaude! Makes a whole lot of sense now (Answer I got: 25.65%)

Steps:
Grams of barium phosphate -> moles of barium phosphate -> moles of ammonium phosphate -> grams of ammonium phosphate.

Then divided grams of ammonium phosphate by grams of fertilizer (multiplied by 100).
 
Last edited:
littlebearrrr said:
(Answer I got: 25.65%)

Looks good.
 
  • Like
Likes 1 person

Similar threads

  • · Replies 14 ·
Replies
14
Views
12K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 12 ·
Replies
12
Views
7K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 1 ·
Replies
1
Views
6K
Replies
1
Views
4K
Replies
3
Views
2K