What is the Period of Oscillation for a Charge in an Electrostatic Field?

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SUMMARY

The discussion focuses on determining the period of oscillation for a charge -q in an electrostatic field created by two fixed charges +Q. The derived formula for the period of oscillation is T = πa√(πε₀ma/Qq), where ε₀ represents the permittivity of free space. The problem emphasizes the importance of considering small displacements and using appropriate force equations to derive the oscillation period. A diagram illustrating the setup is recommended for clarity.

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  • Familiarity with Newton's second law of motion (F = ma).
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Hey guys I'm from Brazil and I'm studying physics to pass in one of the best universities here. However, the physics test is much harder than what we study at school. I am currently working on a book called "Selected Elementary Physics", by MIR Moscou, and I am having a lot of trouble. I don't have anyone who can help me solve these problems, and I am hoping these forums would be a good solution to my problem. I'm from Brazil and my english terminology on Physics is very bad, and I might make bad translations, which I will point out by (?)(?). I'll start with a first one, hoping that it somebody can solve.

Homework Statement


Two equal (?)"Charges"(?) [tex]+Q[/tex] are fixed and located at a distance [tex]a[/tex] from each other. Along the symmetry axis of these charges, a third charge, [tex]-q[/tex], can be moved, which has a mass [tex]m[/tex]. Considering the distance from the [tex]-q[/tex] particle to the line that unites the [tex]+Q[/tex] charges, determine the (?)oscillations period(?) of the [tex]-q[/tex] charge.

Homework Equations


[tex]F\,=\,\frac{1}{4\pi\epsilon}\,.\,\frac{Q\,.\,q}{d^2}[/tex]

The Attempt at a Solution



Since it says the distance is small, I assumed it to be infinetely small, and considered the distance from [tex]+Q[/tex] to [tex]-q[/tex] to be [tex]a[/tex] as well. I then used [tex]F\,=\,m.a[/tex], with no effect. I don't know how to approach this problem, any help is appreciated.

Answer: [tex]\Large{T\,=\,\pia\,\sqrt{\frac{\pi\epsilon _o.m.a}{Qq}}\,.\pi\,.\,a}[/tex]
 
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triplebig said:

The Attempt at a Solution



Since it says the distance is small, I assumed it to be infinetely small, and considered the distance from [tex]+Q[/tex] to [tex]-q[/tex] to be [tex]a[/tex] as well. I then used [tex]F\,=\,m.a[/tex], with no effect. I don't know how to approach this problem, any help is appreciated.

(Pl don't use same symbols for different quantities, like you have used 'a'.)

The distance by which the -q is disturbed is small, and you have considered it to be infinitesimally small, which is all right. From there, how did you jump to equating it to 'a'? Is ‘a’ infinitesimally small?

Draw a diagram. The two +Qs are at A and B. The –q charge is at the midpoint C of AB. Suppose it is displaced to D, where D is on one of the perpendicular bisectors of the segment AB, and CD is very small. Let CD=x and ∟CAD= θ.

Now calculate the vertical, i.e., the force along DC on –q. You get the force equation by equating [itex]m(d^2x/dt^2)[/itex] to that force. Since θ is very small, sin θ ~ θ, and BD ~ BC.

Now you will land up with a familiar equation. You know how to find the time period of such an oscillation.
 

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