What is the period of vibration for a 2.20 kg object on a 320 N/m spring?

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SUMMARY

The period of vibration for a 2.20 kg object attached to a spring with a force constant of 320 N/m can be calculated using the formula T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. Substituting the given values, T = 2π√(2.20 kg / 320 N/m) results in a period of approximately 0.25 seconds. Understanding the relationship between mass and spring stiffness is crucial for solving problems related to simple harmonic motion.

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Homework Statement



A 2.20 kg object vibrates at the end of a horizontal spring whose force constant is 320 N/m. What is its period of vibration?

Homework Equations


Ep=1/2kx2

The Attempt at a Solution


I don't even know where to start
 
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Well, how's the period of vibration related to mass and stiffness? i.e. what's the "formula" for the period? You should look into how the equations of motion for a simple harmonic oscillator are derived.
 

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