What is the pH of a mixture made with ammonia hydroxide and HCl?

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SUMMARY

The discussion focuses on calculating the pH of a mixture created by combining 25 ml of 0.100M HCl with 100 ml of 0.025M ammonia hydroxide (NH4OH). The concentrations of both reactants in the mixture are determined to be 0.02M. The key reaction is NH4OH + HCl <--> NH4 + H2O + Cl, and the dissociation constant (Kd) for NH4OH is given as 1.76 x 10^-5. The correct approach involves using stoichiometry to identify the limiting reagent and applying the dissociation constant to find the pH.

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Homework Statement


A mixture is made by adding 25 ml of 0.100M HCl to 100ml of 0.025M ammonia hydroxide. Kd = 1.76 x 10^-5 . My task is to calculate the pH.


Homework Equations


I think this is the reaction that follows:
NH4OH + HCl <--> NH4 + H2O + Cl



The Attempt at a Solution


I have calculated the concentrations in the mixture:
c(NH4OH) = (0.025mol/l x 0.100l) / ( 0.100l + 0.025l) = 0.02 mol/l
c(HCl) = (0.100 mol/l x 0.025l) / ( 0.100l + 0.025l) = 0.02 mol/l

NH4OH + HCl <---> NH4 + H2O + Cl
Initial C 0.02M 0.02M 0
final C 0 0 0.02M

After this I'm not sure what happens, I have tried calculating the concentration of hydrogen ions formed by this reaction NH4 <---> NH3 + H ( I guess Kd is for this reaction) and calculating the pH then but it was wrong.
My teacher refuses to help me solve this and won't even tell me where I go wrong.
 
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tyrant said:
I have tried calculating the concentration of hydrogen ions formed by this reaction NH4 <---> NH3 + H

That's the correct approach, question is - what is Kd?
 
I think Kd is a dissociation constant, the task was written as I wrote it to the problem statement. Kd is just given without specifically telling for what reaction it is.
Strangely I can't get the correct answer ( I don't know what the answer should be). I have double checked my calculations and there shouldn't be any errors in them. When I got my calculation back from my teacher there was only one mark and it said "wrong anwer and wrong solution". When I asked where exactly I had gone wrong he just mumbled something like check my lectures and I did but still no idea what seems to be the problem.
 
What if I tell you Kd is for NH4OH dissociation?
 
The Kd being 1.76 x 10^-5 is close enough to the dissociation constant for ammonia in water.

First task is use stoichiometry to determine which is in excess: ammonium hydroxide or HCl? If HCl is in excess, then use simple molarity of the excess HCl to find [H+] and pH. Otherwise, use dissociation constant expression formula to find pH.

Please note that we usually indicate dissociation constant of a weak base using symbol, Kb.
 

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