What Is the Phase Angle in a Low Resistance L-C Series Circuit?

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In a low resistance L-C series circuit, the phase angle can be calculated using the formula tan(theta) = (Xl - Xc) / R. When the resistance R approaches zero, the tangent becomes infinite, leading to a phase angle of -90 degrees, as the voltage across the capacitor exceeds that across the inductor. The discussion highlights that the cosine of the phase angle remains positive due to R being non-negative, which confines the angle between -90 degrees and 90 degrees. As R approaches zero, the angle's tangent trends towards negative infinity, confirming the phase angle's value. Understanding these relationships is crucial for analyzing circuit behavior in low resistance scenarios.
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Phase angle?? L-C series

Homework Statement


In an L-C series circuit with very small resistance, the voltage drops across inductor and capacitor are 100V and 120V,. What's the phase angle?


Homework Equations


tantheta= Xl -Xc)/ R


The Attempt at a Solution



According to book's explanation, tantheta= (Xl -Xc)/ R is infinity..!??

Why?? and the answer is -90degree...
Please explain!:)
 
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XL-XC is negative as the voltage across the capacitor is higher than across the inductor. So the tangent is negative: the angle itself is negative, as its cosine (which is proportional to R) is positive. R is very small, so the tangent is very large, tends to -infinity as R tends to zero. What is the tangent of -90 degree?

ehild
 


ehild said:
XL-XC is negative as the voltage across the capacitor is higher than across the inductor. So the tangent is negative: the angle itself is negative, as its cosine (which is proportional to R) is positive. R is very small, so the tangent is very large, tends to -infinity as R tends to zero. What is the tangent of -90 degree?

ehild

as its cosine is positive?!? what do you mean??

tan(-90) is ERR: DOMAIN on my calculator lol...
 


Have you seen a tangent function plotted out? how does it look very close to 90 degree?

The limit is infinite, if you calculate the tangent of angles closer and closer to 90 degree with your calculator. Try.

The real part of the complex impedance is R; it can not be negative.

The imaginary part is called reactance and denoted by X. For a series circuit, X=XL-XC.

If Z is the magnitude of the complex impedance, and theta is its phase angle, then R=Z*cos(theta), X=Z*sin(theta).


X/R= Z*sin(theta)/(Z*cos(theta))= sin(theta)/cos(theta)=tan (theta)

As R >=0, the cosine of the phase angle is positive: The angle must be between -90degree and 90 degree.

As tan(theta)=X/R, you can calculate the angle as the arctangent of X/R if R is finite. If it is zeo, the angle is either 90 of -90 degree.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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