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What is the phase of the SHM at that point

  1. Apr 22, 2013 #1
    1. The problem statement, all variables and given/known data

    A mass is attached to a spring on a frictionless horizontal surface. The mass is pulled to stretch the spring by 0.1 m, & then gently released. A short time later, as the mass passes through the equilibrium position, its speed is 1 m/s.

    Part a)

    What is the speed of the mass at the point where the spring is compressed by 0.05 m?

    Part b)

    What is the phase of the SHM at that point, relative to a phase of zero at the time of release?

    2. Relevant equations

    3. The attempt at a solution

    Part a)

    A = 0.1 m
    ωA =1 m/s
    ω = 1 / 0.1 = 10 rad/s
    y = 0.05 m
    V = ω √ (A2 - y2)
    = 10 * [ √ ( 0.01 - 0.0025 ) ]
    = 0.866 m/s, this answer is correct because my teacher gave us the answer.

    Part b)

    Answer = 120°, how to get this answer?
  2. jcsd
  3. Apr 22, 2013 #2


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    Science Advisor
    Homework Helper

    Hi Voltrical! :smile:
    shm is amplitude times cosωt …

    so won't it have something to do with cos120° ? :wink:
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