What is the physical meaning of the position operator in QFT?

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Discussion Overview

The discussion revolves around the physical meaning of the position operator \( X_\mu \) in quantum field theory (QFT). Participants explore its implications, how it relates to other concepts in QFT, and the nature of the position operator in this context.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the physical meaning of the position operator \( X_\mu \) in QFT, specifically asking whose position it measures.
  • Another participant suggests that in QFT, the position operator is demoted to a parameter, similar to time in classical quantum mechanics, while the wave function is promoted to an operator.
  • A different participant acknowledges the idea of position as a parameter but emphasizes the importance of the position operator whose eigenstate is \( |x\rangle \) and refers to its role in the expression involving the field operator \( \phi(x) \).
  • Another contribution highlights that in QFT, fields are less significant than correlation functions, questioning the probability of detecting a particle created at position \( x \) at position \( x' \).

Areas of Agreement / Disagreement

Participants express differing views on the role and interpretation of the position operator in QFT, indicating that multiple competing perspectives remain without a consensus.

Contextual Notes

Participants discuss the position operator in relation to the wave function and correlation functions, but there are unresolved aspects regarding its physical interpretation and implications in QFT.

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I'm reading some QFT and have been puzzled by the following question:
What's the physical meaning of the position OPERATOR X_\mu in QFT? whose position does it measure?:confused: Thanks for any help.
 
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I believe, in QFT, that in order to obtain sensible results, you end up demoting the position operator into a parameter of the problem, like time in "classica" quantum mechanics, while you promote the wave function to the status of an operator.
 
Thanks, StatMechGuy, I agree on the point you talked about, there is a 'position' that simply is the parameter for the position dependent operator function \phi(x). But what I asked about is the position OPERATOR whose eigenstate is |x>, that's the operator in the expression: <x'|\phi|x''>=\delta(x'-x'')\phi(x')
 
In qft the fields really don't mean much, it is correlation function we are looking to calculate. We ask the question, if a particle is created at x, what is the probably it will be destroyed (detected) at x'. This will be proportional to

<0|Psi(x)Psi+(x)|0>=-iG(x,x')
 

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