What Is the Plane's Constant Acceleration During Takeoff?

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The discussion focuses on calculating an airplane's constant acceleration during takeoff, given the angle of a pocket watch and the time before the plane leaves the runway. Participants emphasize the relationship between the forces acting on the watch, including gravity and the acceleration of the plane, which can be analyzed using vector components. The challenge arises from the lack of mass information for the watch, but it is suggested to express forces in terms of an arbitrary mass variable. A specific example is provided, referencing a watch with a known mass to illustrate the calculation process. The conversation highlights the importance of understanding force dynamics in solving the problem.
asheik234
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Homework Statement


An airplane begins its takeoff sequence moving with a constant acceleration a. A passenger holds up a pocketwatch during the takeoff sequence and notices that the watch makes an angle θ = 14° with the vertical, and that 13.3 seconds pass before the plane leaves the runway.

(a) What is the plane's constant acceleration?


(b) How far does the plane travel on the runway?


Homework Equations



F = ma

The Attempt at a Solution



There is no given mass, I don't know how to find it without it.
 
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The watch lanyard makes an angle determined by two perpendicular forces. One force is due to gravity acting on the watch's mass, m, the other due to acceleration of that same mass.
 
NascentOxygen said:
The watch lanyard makes an angle determined by two perpendicular forces. One force is due to gravity acting on the watch's mass, m, the other due to acceleration of that same mass.

Yes, but when you don't have the mass of the watch itself, how would you be able to solve it, all it gives you is the angle measure and the force of gravity, which is 10.

Here's a picture if it helps,

Frensley_Forces_Horizontal_006.gif
 
asheik234 said:
Yes, but when you don't have the mass of the watch itself, how would you be able to solve it,
Then you call its mass m kg, and work out the vector forces due to gravity and horizontal acceleration both in terms of m kg. What will the magnitudes of each force be?
 
asheik234 said:
Yes, but when you don't have the mass of the watch itself, how would you be able to solve it, all it gives you is the angle measure and the force of gravity, which is 10.

Here's a picture if it helps,

Frensley_Forces_Horizontal_006.gif

Don't forget that the person across the aisle, holding their watch up like you, will see their watch hang at the same angle, and their watch has a mass of precisely 0.21 kg. Does that help?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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