Adrianna said:Homework Statement
A light plane must reach a speed of 33 m/s for takeoff. How long a runway is needed if the (constant) acceleration is 3.0m/s^2?
The Attempt at a Solution
I am not sure how to start it, this is always my problem I can't seem to figure out what formula to use.
Adrianna said:vf^2 = Vi^2 +2ad...?
Adrianna said:I got 1.8 m/s and that's the right answer thanks so much for the help
Motion at constant acceleration refers to the movement of an object at a steady rate of change in velocity. This means that the object is accelerating at a constant rate, either increasing or decreasing its velocity by the same amount over equal intervals of time.
The main difference between constant acceleration and uniform motion is that in constant acceleration, the velocity is changing at a steady rate, while in uniform motion, the velocity remains constant. In other words, in uniform motion, there is no acceleration.
The acceleration in motion at constant acceleration can be calculated using the formula a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time. This formula can also be rearranged to solve for any of the variables.
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that a greater force will result in a greater acceleration, while a greater mass will result in a smaller acceleration.
Some real-life examples of motion at constant acceleration include a car accelerating from a stop, a ball rolling down a hill, and a rocket launching into space. These all involve a steady change in velocity over time, resulting in constant acceleration.