Motion at Constant Acceleration Question 2

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Homework Help Overview

The problem involves determining the length of a runway required for a light plane to reach a takeoff speed of 33 m/s under constant acceleration of 3.0 m/s². The context is rooted in kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to relate final velocity, initial velocity, acceleration, and displacement. There is uncertainty about which equation to apply and how to manipulate it to find the required distance.

Discussion Status

Some participants have attempted to identify relevant kinematic equations, while others express confusion about the initial steps. Guidance has been offered regarding the relationship between the quantities involved, but no consensus on a complete solution has been reached.

Contextual Notes

There is a noted confusion regarding the units of the final answer, with participants clarifying the distinction between meters and meters per second.

Adrianna
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Homework Statement


A light plane must reach a speed of 33 m/s for takeoff. How long a runway is needed if the (constant) acceleration is 3.0m/s^2?


Homework Equations


I looked at the Kinematics Equations and tried to re-arrange them to be able to find the distance with what I was given.


The Attempt at a Solution


I am not sure how to start it, this is always my problem I can't seem to figure out what formula to use.
 
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Adrianna said:

Homework Statement


A light plane must reach a speed of 33 m/s for takeoff. How long a runway is needed if the (constant) acceleration is 3.0m/s^2?


The Attempt at a Solution


I am not sure how to start it, this is always my problem I can't seem to figure out what formula to use.

You have a final velocity, an initial velocity (the plane should be at rest) and an acceleration. You want to find a displacement.

Which of the kinematic equation contains those 4 quantities?
 
vf^2 = Vi^2 +2ad...?
 
Adrianna said:
vf^2 = Vi^2 +2ad...?

So when you use that, what do you get for 'd'?
 
v^2 = 0 * 2as
where v is final velocity, a is acceleration and s is the distance
 
I got 1.8 m/s and that's the right answer thanks so much for the help
 
Adrianna said:
I got 1.8 m/s and that's the right answer thanks so much for the help

you mean you got 1.8m. m/s are the units for velocity.
 

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