What Is the Plane's Constant Acceleration During Takeoff?

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Homework Help Overview

The problem involves an airplane's takeoff sequence characterized by constant acceleration. A passenger observes the angle of a pocket watch during this process, and the scenario includes a time duration before the plane leaves the runway.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the angle of the watch and the forces acting on it, including gravitational force and the force due to acceleration. There are questions about how to proceed without knowing the mass of the watch, and suggestions to express forces in terms of the unknown mass.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the forces involved and questioning the implications of not having the mass of the watch. Some guidance has been provided regarding the vector forces, but no consensus or resolution has been reached.

Contextual Notes

Participants note the absence of mass information for the watch and the reliance on the angle and gravitational force for analysis. There is also a reminder about maintaining thread organization within the forum.

asheik234
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Homework Statement


An airplane begins its takeoff sequence moving with a constant acceleration a. A passenger holds up a pocketwatch during the takeoff sequence and notices that the watch makes an angle θ = 14° with the vertical, and that 13.3 seconds pass before the plane leaves the runway.

(a) What is the plane's constant acceleration?


(b) How far does the plane travel on the runway?


Homework Equations



F = ma

The Attempt at a Solution



There is no given mass, I don't know how to find it without it.
 
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The watch lanyard makes an angle determined by two perpendicular forces. One force is due to gravity acting on the watch's mass, m, the other due to acceleration of that same mass.
 
NascentOxygen said:
The watch lanyard makes an angle determined by two perpendicular forces. One force is due to gravity acting on the watch's mass, m, the other due to acceleration of that same mass.

Yes, but when you don't have the mass of the watch itself, how would you be able to solve it, all it gives you is the angle measure and the force of gravity, which is 10.

Here's a picture if it helps,

Frensley_Forces_Horizontal_006.gif
 
asheik234 said:
Yes, but when you don't have the mass of the watch itself, how would you be able to solve it,
Then you call its mass m kg, and work out the vector forces due to gravity and horizontal acceleration both in terms of m kg. What will the magnitudes of each force be?
 
asheik234 said:
Yes, but when you don't have the mass of the watch itself, how would you be able to solve it, all it gives you is the angle measure and the force of gravity, which is 10.

Here's a picture if it helps,

Frensley_Forces_Horizontal_006.gif

Don't forget that the person across the aisle, holding their watch up like you, will see their watch hang at the same angle, and their watch has a mass of precisely 0.21 kg. Does that help?
 

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