What is the position of a particle at maximum speed?

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Homework Help Overview

The problem involves determining the position of a particle moving along the x-axis, described by the equation x = 6.0t² - 1.0t³. The specific question is about finding the position when the particle reaches its maximum speed in the positive x direction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between position and velocity, with some suggesting the use of derivatives to find velocity from the position function. There are questions about how to maximize the velocity and the process of setting derivatives to zero to find critical points.

Discussion Status

The discussion is ongoing, with participants exploring the differentiation of the position function to find velocity and considering how to maximize this velocity. Some guidance has been provided regarding the relationship between acceleration and maximum velocity, but clarity on the approach remains to be established.

Contextual Notes

There is a mention of confusion regarding the numbers obtained during attempts to apply Galileo's equations of motion, indicating potential misunderstandings or misapplications of the concepts involved.

jrrodri7
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Homework Statement


The position of a particle moving along the x-axis is given by

x = 6.0t^{2} - 1.0t^{3} , where x is in meters and t in seconds. What is the position of the particle when it achieves its maximum speed in the positive x direction?


Homework Equations



motion equations and derivative/integration ideas from motion.

The Attempt at a Solution

 
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How do you think you would get velocity from that expression?
 
You are given position as a function of time. How is velocity related to position? I think you mentioned derivatives/integrals as things to use.
 
ya i figured the derivative of position is velocity right, but I tried doing that and then using that as galileo's equation of motion, substituting the 12 and 3 for velocity and acceleration...but i kept getting numbers that didn't make sense.
 
Yes, the derivative of the position is the velocity. Now how would you maximize it? Your description of what you did isn't very clear. Can you write it out completely, showing those numbers that 'don't make sense'?
 
the derivative is 12t - 3t^(2). That is velocity, now to maximize the equation take the derivative of it? and use that to plug into the other one?
 
Yes, to maximize something you take it's derivative and set it equal to zero. In this case you are setting the acceleration equal to zero. At maximum velocity, the acceleration is zero.
 

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