What is the potential energy of an electron

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SUMMARY

The potential energy of an electron at point A, located 0.01m from a +2nC charge, can be calculated using the equation U = Vq, where V is the electric potential (1800V) and q is the charge of the electron (approximately -1.6 x 10^-19 C). The correct calculation yields U = 1800V * (-1.6 x 10^-19 C) = -2.88 x 10^-16 J. A common mistake in these calculations is neglecting the sign of the electron's charge, which can lead to incorrect results.

PREREQUISITES
  • Understanding of electric potential and potential energy concepts
  • Familiarity with the equation U = Vq
  • Knowledge of Coulomb's law and the constant K (9.00 x 10^9 N m²/C²)
  • Basic algebra for manipulating equations and performing calculations
NEXT STEPS
  • Review the concept of electric potential and its relationship to potential energy
  • Practice problems involving U = Vq with different charge values
  • Explore the implications of charge signs in electrostatic calculations
  • Learn about common pitfalls in physics calculations and how to avoid them
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics, as well as educators teaching concepts related to electric potential and potential energy.

Foxhound101
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Homework Statement


Part A - (Already solved)
The electric potential at point A is 1800V.

Part B -
What is the potential energy of an electron at point A in the figure?

Point A is .01m away from a charge of +2nC

Homework Equations


V=Uq

U = (Kq1q2)/r

The Attempt at a Solution


I think the problem is, is that I am confused about the difference between electric potential and potential energy. This problem shouldn't be difficult.

So I tried the second equation

U = (9.00*10^9)(1.6*10^-19)(2*10^-9)/.01
U = 2.88*10^-18

But that isn't the answer...I don't know what equation I should use or what I am doing wrong.
 
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Hi Foxhound101,

Foxhound101 said:

Homework Statement


Part A - (Already solved)
The electric potential at point A is 1800V.

Part B -
What is the potential energy of an electron at point A in the figure?

Point A is .01m away from a charge of +2nC


Homework Equations


V=Uq

U = (Kq1q2)/r


The Attempt at a Solution


I think the problem is, is that I am confused about the difference between electric potential and potential energy. This problem shouldn't be difficult.

So I tried the second equation

U = (9.00*10^9)(1.6*10^-19)(2*10^-9)/.01

There's not much detail about the situation here, but one thing I noticed is that you are not putting the sign of the electron in the potential energy equation. For the potential and potential energy the sign is required (unless of course they are just asking for the magnitude for some reason).
 
This time I tried the other equation...

1800 = U / (2*10^-9)
3.6*10^-6 = U

still wrong.

*edit* I made my post while you made yours...>_> Let me look into your post*
 
Foxhound101 said:
http://img410.imageshack.us/my.php?image=54425247kj6.gif

Here is the entire problem. I can do the other 2 parts if I know how to do this part.

I think there are two things wrong here. The first is the sign error I mentioned. But also, this calculation from your first post:



Foxhound101 said:
U = (9.00*10^9)(1.6*10^-19)(2*10^-9)/.01
U = 2.88*10^-18

It looks like a calculation error here; it should not be to the -18 power.

Do you get the right answer now?
 
Alright, thanks for the help. I have the correct answer now. I have the rest of the problem worked out as well.

Man...I wasted so much time on this problem when the only major mistake I made was the negative sign.

Normally MasteringPhysics tells me if the sign is incorrect...
 
Foxhound101 said:
Alright, thanks for the help. I have the correct answer now. I have the rest of the problem worked out as well.

Man...I wasted so much time on this problem when the only major mistake I made was the negative sign.

Normally MasteringPhysics tells me if the sign is incorrect...

Glad to help! And I know it's discouraging to spend so much time on something that turns out to be a seemingly small matter. However, not including the sign is a very common and persistent mistake for potential/potential energy calculations, and it's better to get a warning about it in your mind now before any exams.
 

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