What is the Power Factor of a Series RCL Circuit at 2520 Hz?

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Homework Help Overview

The discussion centers around determining the power factor of a series RCL circuit containing a resistor, capacitor, and inductor at a frequency of 2520 Hz. Participants are exploring the implications of resonance and phase differences in the circuit.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of power factor and its relationship to phase differences between the inductor and capacitor voltages. There is uncertainty about what the question is specifically asking and how to approach the calculation.

Discussion Status

Some participants have offered insights into the relationship between resonance and power factor, noting that at resonance, the phase difference is 90 degrees, which leads to a power factor of zero. Others are clarifying their understanding of the phase relationships and how they affect the power factor.

Contextual Notes

There is mention of resonance conditions and the assumption that the source resistance is matched to the circuit resistance, which may influence the power factor calculation.

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Homework Statement


A series RCL circuit contains a 47.0 resistor, a 2.00 µF capacitor, and a 5.00 mH inductor. When the frequency is 2520 Hz, what is the power factor of the circuit?


Homework Equations


cos(angle)=Vr/Vo
Vr=(IrmsR)
Vo=IrmsZ


The Attempt at a Solution


I know power factor is the cos(angle), but I'm having trouble figuring out what this question is actually asking for
 
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i bet that the power factor is just the phase difference btw inductor and capacitor voltages : )
 
at resonance the power dissipation is maximum (i mean if the source resistance is matched to R).. and the phase difference btw C and L voltages is 90 degrees. which makes a power factor of cos90 = 0?
 
ok i get it know theta is defined as (pi/2 - phi). phi being the phase difference btw C and L voltages. and at resonance, phase difference is pi/2 and that makes power_factor = 1 = Vr/Vo, which implies that all of the source voltage (Vo) is observed on the resistance (Vr), which was expected, since at resonance C and L cancels each other.
 

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