What is the power series for sqrt(x+1) using the square root algorithm?

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To find the power series for sqrt(x+1) using the square root algorithm, one can apply the standard derivative and expansion techniques. The derivative of sqrt(x+1) is 1/(2sqrt(x+1)), which can be expanded into a series. The discussion highlights the use of binomial expansion as an alternative method, but emphasizes the need for clarity on which square root algorithm is being referenced. The conversation also touches on inequalities that can assist in deriving the series. Overall, understanding the specific square root algorithm is crucial for successfully applying it to find the power series.
lilcoley23@ho
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How would you go about finding the power series for sqrt(x+1) by applying the square root algorithm. I can do it using binomial expansion and other formulas but I'm not familiar with the square root algorithm involving variables.
 
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Which square root algorithm do you mean? There are several.
 
lilcoley23@ho said:
How would you go about finding the power series for sqrt(x+1) by applying the square root algorithm. I can do it using binomial expansion and other formulas but I'm not familiar with the square root algorithm involving variables.

\int\sqrt{x+1}\rightarrow \frac{2}{3}(x+1)^{\frac{1}{2}}

It's just the usual 1/n+1x^n+1.

and nx^n-1

\frac{d}{dx} \sqrt {x+1} \rightarrow \frac{1}{2(x+1)^\frac{1}{2}}

Which you can expand to a series using the inequality:

(2x + r) r\leq a - x^2
 
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