What Is the Precession Radius of a Spinning Stick with Given Parameters?

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Raihan amin
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Homework Statement


A stick of length 2L and of mass M spins with angular velocity ω around the axis perpendicular to the COM of the stick.It is rotating with making an angle Θ,with the axis parallel to Z axis.The COM has an initial velocity v=υ(to the y axis).Find it's precession radius R.

Homework Equations

.
Angular momentom L=IW
Again L=mυR and [/B]
τ=δL/δt

The Attempt at a Solution


I figure out the torque τ and the change of angular momentum .then i find the gyroscopic relationship W=mgr/Iω
Please help me to find the things out.
Thanks.[/B]
 
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Raihan amin said:
A stick of length 2L and of mass M spins with angular velocity ω around the axis perpendicular to the COM of the stick.
Do you really mean to say this? The COM is a point; an axis cannot be perpendicular to it but can only pass through it. It would help if you posted a drawing showing ##\vec \omega## as a straight arrow to clarify the spin axis. Could it be that the spinning stick is to be treated as a spinning top precessing in the Earth's gravitational field? In that case one end must rest on a horizontal plane and the stick must have a non-zero moment of inertia about its axis.
 
kuruman said:
Do you really mean to say this? The COM is a point; an axis cannot be perpendicular to it but can only pass through it. It would help if you posted a drawing showing ##\vec \omega## as a straight arrow to clarify the spin axis. Could it be that the spinning stick is to be treated as a spinning top precessing in the Earth's gravitational field? In that case one end must rest on a horizontal plane and the stick must have a non-zero moment of inertia about its axis.
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Sorry.here the question has some mistake itself.The right version is as follows:
The stick is spinning with angular velocity ω .And the aerodynamic lift coefficient is C. Here gravity should be neglected because the perpendicular part of lift force equate the weight of the stick.