What is the probability of a security pass being yellow or having a chain?

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SUMMARY

The discussion centers on calculating the probability of security passes being yellow or having a chain. The probabilities provided are 6/10 for passes having a clip, with 2/3 of white passes and 4/7 of yellow passes fitted with clips. The user seeks to determine the probability of a pass being yellow and the probability of a yellow pass having a chain. Additionally, they inquire about the probability of one pass being yellow and the other white when two people are stopped, highlighting the complexity of the problem due to the lack of specific quantities for yellow and white passes.

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Homework Statement


The security passes for a certain company are coloured yellow or white, they're provided with either a clip or a chain. The probability that a pass has a clip is 6/10, 2/3 of the white passes and 4/7 of the yellow ones are fitted with clips. A member of the company is stopped on his way into work find the probability that;

The pass is yellow
The pass is yellow with a chain

If two people are stopped randomly as they enter find the probability that one pass will be yellow and the other white, and one will have a clip and the other a chain.

Homework Equations



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The Attempt at a Solution



Really frustrating question, is this question possible? :/ This is what I've tried, but it's wrong according to the book;

(3/7 * 4/10) + (4/7 * 6/10) = 0.514 (I know this is wrong but I was trying anything)

I just don't see how this is possible because surely it's dependent on the actual number that are white and yellow? Surely if there's 1000 white, and 5 yellow, the probability of a yellow is much different than with different numbers there, and they tell you no-where what to assume...

Any help would be great.
 
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Got it, sorry, i always post too early.
 

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