What Is the Probability of Exactly Two Matching Cards in Envelopes?

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SUMMARY

The probability of exactly two matching cards in envelopes, where 10 cards (5 red and 5 green) are randomly placed in 10 envelopes (5 red and 5 green), can be calculated using combinatorial methods. The sample space is determined by the formula 14C5 x 14C5. The number of favorable outcomes for matching colors is calculated as 25 x (8C4 + 7C3 + 6C2 + 5C1 + 1)^2. The final probability is derived by dividing the number of favorable outcomes by the total sample space, (14C5)^2. The problem can also be approached using hypergeometric distribution principles.

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Homework Statement


Suppose that 10 cards, of which 5 are red and 5 are green, are placed at random in 10 envelopes, of which 5 are red and 5 are green. Determine the probability that EXACTLY two envelopes will contain a card with a matching color.


Homework Equations






The Attempt at a Solution



I know that the size of the sample space is 14C5 X 14C5. I know that there are 5X5=25 ways to select two envelopes of different colors. If there is only one red card in the red envelope, then the other red cards must be located in the green envelopes (since the problem specifies "exactly") with 8C4 possible ways. For all the cases:

1 red: 8C4
2 red: 7C3
3 red: 6C2
4 red: 5C1
5 red: 1

Therefore, there are 8C4+7C3+6C2+5C1+1 ways to satisfy the red card in red envelope condition. The same number of ways holds for the green card in the green envelope condition.

So, in all, there are 25 X (8C4+7C3+6C2+5C1+1)^2 events in the sample space that satisfy the problem's constraints. So, the probability is just the latter number over (14C5)^2.

How wrong is my answer?
 
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I think I would look at the problem this way. Just take 5 red envelopes. Selecting 5 cards at random from the 10, what is the probability of getting exactly 1 red? Looks like a hypergeometric distribution to me.
 

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