Your question is unclear. Do you mean at least one each of 1, 2, 3, 4? Exactly one of each?MilenaMath said:What is the probability of getting 1,2,3,4 when 5 dice are thrown and one of them is not 5.(the order of 1,2,3,4 doesn't matter)
MilenaMath said:I need to get exactly 1,2,3,4(order doesn't matter) and the fifth dice can be whatever number but 5
The probability of getting exactly 1, 2, 3, 4 when 5 dice are thrown is 0.00032 or 0.032%. This can be calculated by taking the total number of ways to get 1, 2, 3, 4 (4) and dividing it by the total number of possible outcomes (1296).
Yes, it is possible to get all 1, 2, 3, 4 when 5 dice are thrown. The probability of this happening is 0.00016 or 0.016%. This can be calculated by taking the total number of ways to get all 1, 2, 3, 4 (1) and dividing it by the total number of possible outcomes (1296).
There are 1296 different combinations that can be made when throwing 5 dice. This can be calculated by taking the total number of possible outcomes for one die (6) and raising it to the power of the number of dice (5).
The probability of getting at least one 1, 2, 3, 4 when 5 dice are thrown is 0.99074 or 99.074%. This can be calculated by subtracting the probability of not getting any 1, 2, 3, 4 from 1. The probability of not getting any 1, 2, 3, 4 is 0.00016 (calculated in question 2), so 1 - 0.00016 = 0.99074.
As the number of dice thrown increases, the probability of getting 1, 2, 3, 4 also increases. This is because the more dice that are thrown, the more possible combinations there are to get 1, 2, 3, 4. For example, if 10 dice are thrown, the probability of getting 1, 2, 3, 4 is 0.000000000000000064 or 0.0000000000064%. This can be calculated by taking the total number of ways to get 1, 2, 3, 4 (4) and dividing it by the total number of possible outcomes (60,466,176).