What Is the Probability of Three Girls Given the Youngest Is Female?

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Discussion Overview

The discussion revolves around a probability problem involving a family with four children, specifically calculating the probability of having three girls given that the youngest child is female. The scope includes mathematical reasoning and exploratory approaches to probability theory.

Discussion Character

  • Mathematical reasoning
  • Exploratory
  • Debate/contested

Main Points Raised

  • One participant initially calculated the probability as 0.375 based on combinatorial reasoning, suggesting that three out of two children must be female.
  • Another participant proposed a different approach, calculating the probability of having three girls and one boy as 1/4 without prior information and 3/8 when knowing one child is female.
  • A third participant provided a systematic enumeration of possible gender combinations, concluding that the probability of having three girls is 3/8, based on the assumption of equal likelihood for boys and girls.
  • A later reply indicated satisfaction with the explanations provided, suggesting clarity was achieved.

Areas of Agreement / Disagreement

Participants presented different methods and calculations for the same probability problem, leading to multiple interpretations of the solution. No consensus was reached on a single approach or answer.

Contextual Notes

Participants did not explicitly resolve the differences in their calculations or assumptions regarding the probability model, leading to potential ambiguity in the interpretations of the problem.

annie122
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i got the answer to the following problem wrong:
"there are four children in in the family. what is the probability that there are three girls, given that the youngest child is female?"

my (updated) answer:
the youngest is female, so three out of two children must be female. there are three ways of this happening, (=3C2) so, the answer is (1/2) ^3 * 3 = .375

also, how do i determine if two variables are positively correlated?
 
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Re: two probabilities question

Yuuki said:
i got the answer to the following problem wrong:
"there are four children in in the family. what is the probability that there are three girls, given that the youngest child is female?"

my (updated) answer:
the youngest is female, so three out of two children must be female. there are three ways of this happening, (=3C2) so, the answer is (1/2) ^3 * 3 = .375

also, how do i determine if two variables are positively correlated?

Lets suppose that the probability of child male and child female is the same, i.e. $p = \frac{1}{2}$. If no information is allowable, then the probability to have three girls and one boy is... $\displaystyle P = \binom{4}{3}\ \frac{1}{16} = \frac{1}{4}\ (1)$

However if You know a priori that one is famale, the probability to have three girls and one boy is the probability to have two girls and one boy among the remaining childs and it is... $\displaystyle P = \binom {3}{2}\ \frac{1}{8} = \frac{3}{8}\ (2)$ Kind regards $\chi$ $\sigma$
 
Re: two probabilities question

Here is another way to do this: writing "G" for "girl", "B" for "boy", in order from youngest to oldest we could have
GGGG
GGGB
GGBG
GGBB
GBGG
GBGB
GBBG
GBBB
The first letter is always "G" because we are told that the youngest child is a girl. The others have 2^3= 8 possible orders giving 8 possible situations. Of those 8, exactly three have 3 "G" (GGGB,, GGBG, GBGG). Assuming that boys and girls are equally likely the probability of "three girls" is 3/8= 0.375.

(If the problem were "at least three girls" we would include "GGGG" so the probability would be 4/8= 0.5.)
 
Re: two probabilities question

thanks, I'm cleared now :)
 

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