What is the radius of a circle with an area of 154 square centimeters?

  • Thread starter Thread starter Superman89
  • Start date Start date
  • Tags Tags
    Assistance
AI Thread Summary
To find the radius of a circle with an area of 154 square centimeters, the formula A = πr² is used. Substituting A = 154 into the equation leads to r² = 154/π. By approximating π as 22/7, the equation simplifies to r = sqrt(7 * 154 / 22). Ultimately, the radius is determined to be 7 centimeters.
Superman89
Messages
17
Reaction score
0
I need help with this word problem.

What is the radius of a circle whose area is 154 square centimeters?
I know I'm suppost to use the formula A={\pi}r^2.
What do I need to do next?
 
Mathematics news on Phys.org
You know that A (the area) is 154 (square centimetres) so its merely a case of substituting A=154 into the formula and solving for r (given that {\pi} is a known value).
 
154 = π r^2

r^2 = 154 / π

r = sqrt(154 / π)

r = sqrt(7 * 154 / 22) [as π = 22 / 7 (approximately)]

r = sqrt(7 * 7)

r = 7cm
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top