What is the Radius of a Long Solenoid with a Given Induced Electric Field?

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SUMMARY

The radius of a long solenoid can be determined using the relationship between the induced electric field and the changing magnetic field. Given the magnetic field strength B = 5.0t T and an induced electric field of 11 V/m at a distance of 2.0m from the axis, the radius can be calculated using the equation E_inside = r/2 |dB/dt|. By substituting the values, the radius of the solenoid is found to be 0.44 meters.

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  • Understanding of electromagnetic induction principles
  • Familiarity with the equations of electric and magnetic fields
  • Knowledge of calculus for differentiation
  • Basic physics concepts related to solenoids
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Homework Statement



For a long solenoid, the magnetic field strength within the solenoid is given by the equation B = 5.0t T, where t is time in seconds. If the induced electric field outside the solenoid is 11 V/m at a distance 2.0m from the axis of the solenoid, find the radius of the solenoid.

Homework Equations



E_inside = r/2 |dB/dt|


The Attempt at a Solution



I know how to calculate the electric field outside the solenoid, but how can I associate the magnetic field inside of it with the electric field outside?
 
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raisen said:

Homework Statement



For a long solenoid, the magnetic field strength within the solenoid is given by the equation B = 5.0t T, where t is time in seconds. If the induced electric field outside the solenoid is 11 V/m at a distance 2.0m from the axis of the solenoid, find the radius of the solenoid.

Homework Equations



E_inside = r/2 |dB/dt|


The Attempt at a Solution



I know how to calculate the electric field outside the solenoid, but how can I associate the magnetic field inside of it with the electric field outside?

Assume that the magnetic flux through the 2.0 m circle extends only over the cross-sectional area of the solenoid.
 

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