What is the Radius of Bohr Atom Orbitals?

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SUMMARY

The radius of the Bohr atom orbitals can be calculated using the formula Rn = a0 x n², where a0 is the Bohr radius (5.3 x 10^-11 m). For the first five orbitals, the radii are as follows: R1 = 5.3 x 10^-11 m, R2 = 2.12 x 10^-10 m, R3 = 4.77 x 10^-10 m, R4 = 9.12 x 10^-10 m, and R5 = 1.53 x 10^-9 m. Additionally, for n=100, the radius is calculated to be 5.3 x 10^-9 m. The quantization of electron orbitals restricts electrons to specific energy levels, preventing them from existing in non-integer orbital states.

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  • Understanding of quantum physics principles
  • Familiarity with the Bohr model of the atom
  • Basic algebra for manipulating equations
  • Knowledge of the concept of quantization in physics
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  • Learn about electron configurations in multi-electron atoms
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aisha1929
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Homework Statement



Given the numerical value of a0= 5.3X10^11m in the Bohr hydrogen atom, find the radius of the first five orbitals as well as the radius for n=100.

Homework Equations



Rn=a0 x n^2

The Attempt at a Solution


Could it be as simple as typing in for the third orbital 3 as n? Meaning the radius for the third orbital will be Rn= 5.3X10^11 x 3^2 = 4.77x10^12m ?
 
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welcome to PF, aisha1929

and yes, it really is that simple :)

one of the things about quantum physics and electron orbitals is that they are "quantized" meaning that there are specific values for which things can actually have. The electron can only be in one of those orbitals, it can't be orbiting the nucleus in, like, orbital shell 2.83 or shell 4.19, etc.

things are stuck in discrete levels or directions or shells, etc.
 

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