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Angular velocity of an Electron

  1. May 18, 2010 #1
    1. The problem statement, all variables and given/known data

    In the Bohr Model of the Hydrogen Atom, a single Electron orbits a circle round a single stationary Proton. If the radius of the electron's orbit for its lowest energy state (the "ground state") is 5.3x10^-11m, find the the constant speed, v , of the orbiting electron .


    2. Relevant equations

    and calculate its kinetic energy in electron volts


    3. The attempt at a solution

    constant speed = angular velocity x radius (5.3x10^-11)
     
  2. jcsd
  3. May 18, 2010 #2
    The orbit also depends on the force on the particle
     
  4. May 18, 2010 #3
    so how would i get the acceleration to use F = ma?
     
  5. May 18, 2010 #4
    Well sort of. You know that the net force is F = ma, but you should also know how the force (or radial acceleration) on a particle in a circle path is related to its velocity. Also apply Coulomb's law and you should be able to solve for the velocity
     
  6. May 18, 2010 #5
    F = m*(v^2/r)?
     
  7. May 18, 2010 #6
    Do you have the mass of the electron, and the charge of the electron and proton?
     
  8. May 18, 2010 #7
    9.11x10^031kg Mass of electron

    1.6x10^-19 electron + proton?
     
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