What Is the Radius of the Amusement Park Ride?

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Homework Help Overview

The discussion revolves around a physics problem involving centripetal force and the radius of a spinning amusement park ride. The scenario describes a person experiencing a force while seated in a chamber that rotates around a central axis.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the radius using the centripetal force formula but questions the correctness of their result. Some participants point out potential errors in the calculations, specifically regarding the squaring of the velocity and the arrangement of the equation.

Discussion Status

Participants are actively engaging with the problem, offering insights into the calculations and suggesting that the original poster reconsider their approach. There is a focus on clarifying the mathematical relationships involved without reaching a definitive conclusion.

Contextual Notes

There is an indication that the original poster may have misunderstood the application of the formula, particularly in terms of squaring the velocity and the arrangement of variables. The discussion is framed within the context of a homework problem, which may impose specific constraints on the methods used.

rockmorg
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I have a question on what it is I might be doing wrong here... I've tried this answer in the grader and it is wrong...

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.2 m/s and an 83 kg person feels a 495 N force pressing against his back. Radius of the chamber?

Here is what I have done..

v = 3.2 m/s
m = 83 kg
F = 495 N
r = ?

Fc = mv2/r
r = Fc(1/mv2)

r = 495 N (1/(83kg * 3.2 m/s2))
r = .582 m

Even just looking at it it looks wrong, heh...

Any help would be great!

Thanks,
-
Morgan
 
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Notice this:

F = m \frac{v^2}{r}

\frac{r}{F} F = \frac{r}{F} m \frac{v^2}{r}

r = m \frac{v^2}{F}
 
I was just going to say that it looks like you didn't square the velocity.
 
Ahhh thanks much - so I guess it was just a matter of arranging my equation? The mass needs to multiply out to those other variables for it to work...
 

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