What is the ratio between tensions in different positions for a swinging ball?

• konichiwa2x
In summary: I'm not sure exactly how the interpret shramana's words, but the idea expressed by the equations is the same. yup, tension before the cord is cut. Otherwise, the tensions are same right! so T1/T2 = 1..
konichiwa2x
Hi, Can someone please explain how to do this problem? I really don't understand.

A ball is held at rest in position A as shown in the figure by 2 light cords. The horizontal cord is cut and the ball swings as a pendulum. What is the ratio of the tensions in the supporting cord, in position A, to that in position B?

http://img445.imageshack.us/img445/3927/lomprobtensionvx9.png

Last edited by a moderator:
konichiwa2x said:
Hi, Can someone please explain how to do this problem? I really don't understand.

A ball is held at rest in position A as shown in the figure by 2 light cords. The horizontal cord is cut and the ball swings as a pendulum. What is the ratio of the tensions in the supporting cord, in position A, to that in position B?

I assume they want you to compare the tension at A before the horizontal cord is cut to the tension at B. Otherwise, it is not much of a problem. At A, the net force is zero. At B, the ball is accelerating in the direction of the arc. Compare the forces in the two cases.

In case-1, T1cosx=mg, while in case-2, T2=mgcosx because in case-2, T cannot be resolved while mg can be resolved as there is resultant acceleration. So T1/T2=secx*secx. Its a situation of temporary rest.

thanks

I had earlier done this for case 2: Tcosx=mg. why is that wrong? can't tension be resolved along the vertical?
T cannot be resolved while mg can be resolved as there is resultant acceleration.

I assume they want you to compare the tension at A before the horizontal cord is cut to the tension at B. Otherwise, it is not much of a problem
yup, tension before the cord is cut. Otherwise, the tensions are same right! so T1/T2 = 1..

At B, the ball is accelerating in the direction of the arc. Compare the forces in the two cases.
but what is causing it to accelerate in the direction of the arc? its own weight?

konichiwa2x said:
thanks

but what is causing it to accelerate in the direction of the arc? its own weight?
Yes. At B, the weight has a component in the direction of the arc, and a component perpendicular to the arc (in the direction of the string). The ball is not accelerating perpendicular to the arc, so what does that tell you about the sum of the forces in that direction?

I'm not sure exactly how the interpret shramana's words, but the idea expressed by the equations is the same. I think he is just saying that in one case you are going to resolve the vectors in one set of directions, and in the other case you are going to resolve them in a different set. In fact you could resolve them in the same set of directions in both cases and get the same result. It is just easier to do the two cases with different directions, keeping one force "unresolved" in both cases.

1. What is tension in a string with a ball?

Tension in a string with a ball refers to the force being applied to the string when the ball is attached to it. It is the result of the weight of the ball pulling down on the string and the string's resistance to being stretched.

2. How is tension affected by the weight of the ball?

The tension in the string will increase as the weight of the ball increases. This is because a heavier ball will pull down on the string with a greater force, requiring the string to stretch more to maintain its position.

3. How does the length of the string affect tension?

The tension in the string will decrease as the length of the string increases. This is because a longer string has more surface area to distribute the weight of the ball, resulting in less force being applied to each individual point on the string.

4. What factors can affect tension in a string with a ball?

Aside from the weight and length of the string, other factors that can affect tension include the material and thickness of the string, the angle at which the string is pulled, and any external forces acting on the string such as wind or friction.

5. How is tension measured in a string with a ball?

Tension in a string with a ball can be measured using a tension meter or by calculating the force being applied to the string using Newton's second law of motion (F=ma). The force will be equal to the weight of the ball plus any additional forces acting on the string.

• Introductory Physics Homework Help
Replies
7
Views
8K
• Introductory Physics Homework Help
Replies
9
Views
778
• Introductory Physics Homework Help
Replies
2
Views
1K
• Introductory Physics Homework Help
Replies
4
Views
5K
• Introductory Physics Homework Help
Replies
24
Views
2K
• Introductory Physics Homework Help
Replies
5
Views
959
• Introductory Physics Homework Help
Replies
10
Views
2K
• Introductory Physics Homework Help
Replies
1
Views
2K
• Introductory Physics Homework Help
Replies
5
Views
3K
• Introductory Physics Homework Help
Replies
5
Views
5K