MHB What is the reference angle for 60° and -60°?

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The reference angle for 60° is calculated as R = 90° - 60°, resulting in a reference angle of 30°. However, the book states the reference angle is 60°. For -60°, the reference angle is found in Quadrant 4, calculated as R = -90° + 60°, yielding -30°, but again the book indicates the reference angle is 60°. The discussion highlights the standard rules for determining reference angles across different quadrants. Additionally, participants inquire about algebraic methods for finding reference angles, which leads to further clarification.
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1. Find the reference angle given 60°.

Let R = reference angle

I decided to graph 60°. We are in Quadrant 1.

R = 90° - 60°

R = 30°

Book's answer for R is 60°.

2. Find the reference angle given - 60°.

I decided to graph - 60°. We are in Quadrant 4.

R = -90° - (-60°)

R = -90° + 60°

R = -30°

Book's answer for R is 60°.
 
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for $0 < \theta < 90$, reference angle is $\theta$

for $90 < \theta < 180$, reference angle is $180-\theta$

for $180 < \theta < 270$, reference angle is $\theta-180$

for $270 < \theta < 360$, reference angle is $360-\theta$

reference-angle.png
 
Helpful picture reply.

Is there an algebraic method for finding the reference angle?
 
RTCNTC said:
Helpful picture reply.

Is there an algebraic method for finding the reference angle?

look at what I posted prior to the pic ...
 
skeeter said:
look at what I posted prior to the pic ...

I see it now. Thanks.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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