I know that when viewing a graph in which velocity is on the y-axis and time is on the axis, the acceleration is the slope of the line. When viewing a graph in which a force is on the y-axis and a time is on the x-axis, (particularly one in which the graphed line makes a triangle) the area is the momentum. Why is it that you use the area formula for momentum and slope formula for acceleration? what is the significance of the area in a v / t graph and the slope in a F / t graph? I have found that applying the area formula to a V / t graph gets you an answer in meters, because (1/2)*(m/s)*(s/1) = (m/2) but I cannot seem to find a scenario in which the area correlates to any part of the problem. In an F/t graph, the units after doing the slope formula would be kgm/s, just like momentum, accept the area is the momentum- not the slope. Any insight?