What is the Relationship Between Energy and Time in Different Frames?

  • Context: Graduate 
  • Thread starter Thread starter chewwy
  • Start date Start date
  • Tags Tags
    Energy Frames
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
chewwy
Messages
6
Reaction score
0
something which seems so fundamental that i can't find anywhere that derives it is the following:

E' = gamma * (E - p.v)

where E is the energy in one frame, p the momentum, v the relative velocity of the other frame, and E' the energy in the other frame.

i.e. energy transforms like time. i can't quite see where this comes from though.. help?
 
Physics news on Phys.org
It comes from the fact that energy is the "zeroth" component of the momentum four-vector [itex](p_0, p_1, p_2, p_3) = (E/c, p_x, p_y, p_z)[/itex], just like time is the "zeroth" component of the position four-vector [itex](x_0, x_1, x_2, x_3) = (ct, x, y, z)[/itex].
 
Welcome to PF!

Hi chewwy! Welcome to PF! :smile:

(have a gamma: γ :wink:)
chewwy said:
energy transforms like time. i can't quite see where this comes from though.. help?

Yes, it's because (E,p) is defined as the derivative of (t,x),

so E' = γE - γ(p.v),

just as t' = γt - γ(x.v)
 
jtbell said:
It comes from the fact that energy is the "zeroth" component of the momentum four-vector [itex](p_0, p_1, p_2, p_3) = (E/c, p_x, p_y, p_z)[/itex], just like time is the "zeroth" component of the position four-vector [itex](x_0, x_1, x_2, x_3) = (ct, x, y, z)[/itex].

okie doke. thanks everyone!