ozkan12
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let f:X to X be and f(X) C X...then f is invariant..if f is invariant, then f is self map on X ? is it true ?
The discussion centers on the relationship between a function \( f: X \to X \) and its properties as a self-mapping or endofunction. It is established that while \( f(X) \subseteq X \) indicates that the image of \( f \) is contained within the set \( X \), it does not necessarily imply that \( f \) is a self-mapping. A function is defined as a self-mapping if both its domain and codomain are the same set \( X \). The terms "invariant set" and "invariant map" are clarified, with the former referring to subsets \( A \) where \( f(A) \subseteq A \).
PREREQUISITESMathematicians, students of mathematics, and anyone interested in understanding the properties of functions and mappings within set theory and metric spaces.
The condition $f(X)\subseteq X$ is superfluous. A function $f$ is called a self-mapping if $f:X\to X$. In this case, $f(X)\subseteq X$ holds automatically.ozkan12 said:that is, for f:X >>>X if f(X)CX then f is selfmapping ?
What is $X$ here?ozkan12 said:İf f(X)⊆X then f is selfmaping ?