What is the relationship between gravity and conservation of momentum?

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SUMMARY

The discussion clarifies the relationship between gravity and the conservation of momentum using the example of a rock falling off a cliff. When the rock falls, it gains momentum downwards due to Earth's gravitational pull, while the Earth gains an equal amount of momentum upwards, maintaining the conservation of momentum in the Earth-rock system. This principle is mathematically expressed as ∂p/∂t = 0, indicating that the total momentum remains constant if no external forces act on the system. The interaction between the rock and the Earth is fundamentally due to gravitational forces, which ensures that momentum is conserved throughout the process.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of momentum and its conservation
  • Basic knowledge of gravitational forces
  • Mathematical representation of momentum, specifically ∂p/∂t
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  • Study the principles of Newton's Third Law of Motion
  • Explore gravitational force calculations using F = G(m1*m2)/r^2
  • Learn about elastic and inelastic collisions in physics
  • Investigate the implications of momentum conservation in closed systems
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Students of physics, educators explaining fundamental concepts, and anyone interested in the mechanics of motion and forces, particularly in relation to gravity and momentum conservation.

Killparis
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Hi.

I am studying physics on my own from scratch, so far so good, though I've run into this concept I am struggling to understand.

If we push a large rock over a cliff, it falls because of the pull of the Earth's gravity on it. This force is its weight and it makes the rock accelerate towards the Earth. Its weight does work and the rock gains kinetic energy. It also gains momentum downwards.

Now, according to the book I use - Cambridge International AS and A level Physics - something must be gaining an equal amount of momentum in the opposite (upward) direction. it is the Earth, which starts to move upwards as the rock falls downwards. When the rock hits the ground, its momentum becomes zero. At the same instant, the Earth also stops moving upwards. The rock's momentum cancels out the Earth's momentum. At all times during the rock's fall and crash-landing, momentum has been conserved.

_____

I understand the principle of conservation of momentum, but I don't quite understand how it relates to this. I am guessing it will have something to do with gravity, but even then, why there has to be an equal amount of momentum in the opposite direction?

Thank you for an explanation.
 
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Killparis said:
it is the Earth, which starts to move upwards as the rock falls downwards.
Yes.
 
Momentum must stay constant in the system (Earth-Rock system). If we start out with a system with zero momentum, it must always have 0 momentum (if there are no external forces). This can be stated mathematically as ##\frac{d\mathbf p}{dt} = 0##.

In order for this to happen, the Earth needs to have ##- \mathbf p## (where the momentum of the rock is ##\mathbf p##) to cancel out the momentum of the rock. If the momentum where different, this would mean that the force is not equal and opposite, and hence we have a change in momentum.
 
Astrum said:
Momentum must stay constant in the system (Earth-Rock system). If we start out with a system with zero momentum, it must always have 0 momentum (if there are no external forces). This can be stated mathematically as ##\frac{d\mathbf p}{dt} = 0##.

In order for this to happen, the Earth needs to have ##- \mathbf p## (where the momentum of the rock is ##\mathbf p##) to cancel out the momentum of the rock. If the momentum where different, this would mean that the force is not equal and opposite, and hence we have a change in momentum.

I understand all of this, but I don't get why the rock should "interact" with the Earth.

The momentum in this book was explained on two colliding objects, so I am struggling to transfer those findings to this example. I mean, if I have a ball rolling towards a wall, the wall clearly doesn't move towards the ball. Yes, I understand that the Earth has gravity which causes the rock to fall towards it, but I can't link these two findings.
 
Killparis said:
I understand all of this, but I don't get why the rock should "interact" with the Earth.

The momentum in this book was explained on two colliding objects, so I am struggling to transfer those findings to this example. I mean, if I have a ball rolling towards a wall, the wall clearly doesn't move towards the ball. Yes, I understand that the Earth has gravity which causes the rock to fall towards it, but I can't link these two findings.

They rock and Earth interact because of gravity. If we have a force ##\mathbf F = \frac{d\mathbf p}{dt}## on the rock, there must be a force ##-\mathbf F= - \frac{d \mathbf p}{dt}## on the Earth. The interaction is through gravity. I'm not sure what you're not understanding.

To use your example of a ball rolling into a wall: Consider a completely elastic collision between a ball and a wall. If the wall rests on a surface without friction, it will have to "recoil" after the collision and take the momentum of the ball, leaving the ball stationary. The interaction is the collision.
 
The rock also has gravity which causes the Earth to fall to the rock.
 
tony873004 said:
The rock also has gravity which causes the Earth to fall to the rock.

This was the puzzle piece I was looking for.

Thank you all, I understand now.
 

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