What is the relationship between polarization vectors and spin in QFT?

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SUMMARY

The discussion focuses on the relationship between polarization vectors and spin in Quantum Field Theory (QFT). The polarization vector is defined as ##s^\mu=(0,\vec s)##, with the condition that ##|\vec s|=1##, indicating that it has no temporal component in Minkowski space. The user seeks to understand how the longitudinal part of the polarization vector contributes to the overall spin state, specifically questioning the calculation of ##s^\mu_L \left(s_L \right)_\mu## and its implications for the squared magnitude of the vector.

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  • Understanding of Quantum Field Theory (QFT)
  • Familiarity with Minkowski space and its metric
  • Knowledge of spin and polarization in particle physics
  • Basic mathematical skills for tensor calculations
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RicardoMP
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Homework Statement
I'm told to consider the polarization vector $$s_L^\mu=(\gamma \beta, \gamma \vec\beta/\beta)$$, which is longitudinal (##\vec s_L||\vec\beta##, where ##\beta## is the relative velocity in a Lorentz boost), and that I want to show that ##s^\mu_L## satisfies ##s^2=-1##.
Relevant Equations
$$s_L^\mu=(\gamma \beta, \gamma \vec\beta/\beta)$$
##s^\mu=(0,\vec s)## and ##|\vec s|=1##
I'm looking forward to have a better understanding of the polarization vector in quantum field theory in order to solve a particular problem.
In class and in several textbooks I see that ##s^\mu=(0,\vec s)## and ##|\vec s|=1##. Are polarizations vectors defined to have no temporal component in Minkowski space and for its modulus to be 1? If I square the longitudinal part I get 0 for which I assume that the only contribution to ##s^2## comes from the transverse part(##s^\mu=s^\mu_L+s^\mu_T##).
How is this polarization vector related to spin and what does it represent in a particle's state?

Thank you and stay safe.
 
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RicardoMP said:
I want to show that ##s^\mu_L## satisfies ##s^2=-1##.
Do you know how to calculate ##s^\mu_L \left(s_L \right)_\mu##?
 

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